Math 110: Calculus 1 (Fall 2007) |
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Home > Assignments> Quizzes |
Quizzes |
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Date Assigned | Date Due | Topic | Hint |
BONUS 4 |
Fri Nov 30 | Mon Dec 3 | Euler's Method (solution) |
HINT: Recall that for a function to be a solution of an IVP it must satisfy the DE and the IC. |
10 |
Mon Nov 19 | Mon Nov 26 | Single Variable Optimization (solution) |
HINT: How do you prove that a function has a global extremum? (Use the first derivative or second derivative test) |
9 |
Thu Nov 15 | Thu Nov 15 | Curve Sketching (solution) |
(in class) |
8 |
Fri Nov 9 | Mon Nov 12 | L'Hopital's Rule (solution) |
HINT: Consider what happens when m=0, m>0 and m<0 separately. |
BONUS 3 |
Fri Oct 26 | Mon Oct 29 | Applications of The Chain Rule (solution) |
HINT: Recall the chain rule is [f(g(x))]'=f'(g(x))g'(x). In related rates problems always notice and make sure the derivatives use the correct units. |
7 |
Thu Oct 25 | Thu Oct 25 | The Chain Rule | (in class) |
6 |
Thu Oct 18 | Thu Oct 18 | Interpreting The Derivative (solution) | (in class) |
BONUS 2 |
Wed Oct 10 | Wed Oct 17 | Rules of Differentiation (solution) | HINT: Recall that f(x)=|x| can really be thought of as a piecewise defined function (when x<0, f(x)=-x, when x>=0 , f(x)=x.) |
5 |
Wed Oct 10 | Wed Oct 17 | Derivative Rules (solution) | HINT: Recall the rules of differentiation (Product, Power, Constant, Constant Multiple and Quotient). |
BONUS 1 |
Fri Oct 5 | Mon Oct 8 | Differentiation and Limits (solution) | HINT: Remember the difference of two squares formula: A2-B2=(A+B)(A-B)! |
4 |
Fri Oct 5 | Mon Oct 8 | Limits, Derivatives and Tangents (solution) | HINT: When the slope of a line A is greater than the slope of line B we can see that line A is STEEPER than line B. |
3 |
Thu Sep 20 | Thu Sep 20 | Limits (solution) | HINT: An indeterminate limit can often be evaluated by using an algebraic relationship between the numerator and denominator to simplify the expression BEFORE taking the limit. (in class) |
2 |
Fri Sep 14 | Mon Sep 17 | Properties of Functions (solution) | HINT: the domain of a composite function is dependent on the domains of the two constituent functions, regardless of what the rules of the constituent functions would indicate is the natural domain. |
1 |
Thu Sep 6 | Thu Sep 6 | Functions (solution) | (in class) |