Quantifier Negation Rules

We discussed the matter of the negation of quantified propositions back in Chapter 7. In the section, "Quantified Negations"  we noted that

~(x)Fx is logically equivalent to (x)~Fx
~(x)Fx is logically equivalent to (x)~Fx

We will refer to these as our basic quantifier negation rules.

In Chapter 8,  we showed that an A categorical proposition is logically equivalent to the negation of an O categorical proposition, and that an E categorical proposition is logically equivalent to the negation of an I categorical proposition. Thus we have the following categorical quantifier negation rules:

(x)(Sx Px) is logically equivalent to ~(x)(Sx & ~Px)
(x)(Sx ~Px) is logically equivalent to ~(x)(Sx & Px)

and it also goes the other way:

~(x)(Sx Px) is logically equivalent to (x)(Sx & ~Px)
~(x)(Sx ~Px) is logically equivalent to (x)(Sx & Px)

These equivalences form the Quantifier Negation Rules (Q.N.R.) for QL. They function just like the Equivalence Rules.  A wff can be replaced with a logically equivalent wff. You can think of teh Q.N.R. as an extention of the Equivalence Rules, but you must cite Q.N.R. specifically when you use a quantifier negation equivalence.

The last four equivalences, the categorical quantifier negation rules, are actually superfluous. We can derive them from a combination of the basic quantifier negation rules and our equivalence rules. Here's a proof of:

~(x)(Sx & ~Px)
(x)(Sx Px)

 

1. ~(x)(Sx & ~Px) Premise
2. (x)~(Sx & ~Px) Q.N.R., 1
3. (x)(~Sx v ~~Px) DeM. 2
4. (x)(~Sx v Px) D.N. 3
5. (x)(Sx Px) C.E. 4

Of course, to show equivalence, we need to show that the biconditional of the two wffs is a theorem. That's left as an exercise for you! And here's a summary of the Quantifier Negation Rules.

 

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