Discrete Mathematics
- Mathematics 210 -
Fall 2010
Extra problems for HW #25
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(I don't know yet which of the following problems will be graded by our grader.)
- Let S be the set of all words of infinite length that only use the letters a and b (e.g., aabaabaabaab... is such a word). Use a diagonalization argument to show S is uncountable.
- Prove that the set of all rational numbers is countable by appropriately modifying the proof given in Example 20 (p. 159).
- Let S be the set of all words of finite length that only use the letters a and b (e.g., abb, and bbbbab are such words). Prove S is countable by using a "listing method" as in Example 20 (p. 159).
- What is wrong with the following "proof" that the set Z of all integers is uncountable? Indicate exactly which step(s) is(are) wrong, and why.
- Suppose, toward contradiction, that Z is countable.
- Then, since Z is not finite, it must be denumerable, by definition of "countable".
- So there is a bijection f : N --> Z, by definition of "denumerable".
- For all i in N, let x_i = f(i). (x_i is "x sub i")
- Let y be the natural number whose ith digit from the right is 1+ the ith digit of x_i from the right, except that if the ith digit of x_i is 9, we choose 8 for the ith digit of y.
- Then y is different from x_i since they differ in at least one digit, namely in their ith digits.
- So y is not equal to any of the numbers x_i.
- So y is not in the range of f.
- So f is not onto.
- But this contradicts step iii.
- So Z is uncountable.
- True or false: if S and T are denumerable sets, then there exists a bijection from S to T. Prove your answer.
- True or false: if S is a countable set and T is an uncountable set, then there exists no bijection from S to T. Prove your answer.